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Question

If tan(x+y)=33 and x=tan13, then y can be

A
π6
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B
π3
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C
tan1(0.3)
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D
tan1(118)
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Solution

The correct option is C tan1(0.3)
tan(x+y)=33
x+y=tan133
y=tan133tan13
y=tan1(3331+333)
y=tan1(30100)
y=tan1(0.3)

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