Question

If ${\text{V}}_{\text{A}}-{\text{V}}_{\text{B}}=3\text{volt}$ , the potential difference across the terminals of the battery is:

• A. 18 volt
• B. 9 volt
• C. 27 volt
• D. 36 volt

Answer 1

The correct option is C 27 volt

$V_A-V_B=3V$

$\frac{4\times 3}{4+3}=\frac{12}{7}$

$\frac{12}{7}+\frac{12}{7}+C$

$V_A-V_B=3V$

$Q_{eq}=3\times 3=9C$

Now, $V=(3\times 9)V$

$=27V$