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Question

If (23sin2x)sec xdx=2f(x)g(x)+c and f(x) is non constant function then

A
f2(x)+g2(x)=1
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B
f2(x)g2(x)=1
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C
f(x)+g(x)=1
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D
f(x)+g(x)
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Solution

The correct option is A f2(x)+g2(x)=1
(23sin2x)cosxdx=2cos2xsin2xcosxdx=2(cosx)cosxdxsin2xcosxdx=2sin xcosx+cf(x)=sin x,g(x)=cos x

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