If the 0.05 M solution of M $^{+}$ is replaced by a 0.0025 M solution of M $^{+}$ , then the magnitude of the cell potential would be:

35 mV

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70 mV

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140 mV

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700 mV

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Solution

The correct option is C 140 mV
$M (s) | M_{a q}^{+} (0.05 M) | | M_{a q}^{+} (1 M) | M (s)$

$| E_{c e l l} | = 70 m V$ means may be +ve or -ve

According to Nernst equation:
$E = E^{o} - \frac{0.0591}{n} \times l o g Q$

$E_{c e l l} = E_{O P_{L H S}} + E_{R P_{R H S}}$
$= E_{O P}^{o} - \frac{0.059}{1} l o g [M^{+}]_{L H S} + E_{R P}^{o} + \frac{0.059}{1} l o g [M^{+}]_{R H S}$

$= 0.059 l o g \frac{[M^{+}]_{R H S}}{[M^{+}]_{L H S}}$

$E_{c e l l} = 0.059 l o g \frac{1}{0.0025} = 0.059 l o g \frac{1}{(0.05)^{2}}$
$= 2 \times 76 m V = 153 ≃ 140 m V$

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Similar questions

Q. If the 0.05 molar solution of

M^{+}

is replaced by 0.0025 molar

M^{+}

solution, then the magnitude of the cell potential would be:

Q. If the

0.05

molar solution of

M^{+}

is replaced by a

0.0025

molar

M^{+}

solution, then the magnitude of the cell potential would be__________.

The concentration of potassium ions inside a biological cell is at least twenty times higher than the outside. The resulting potential difference across the cell is important in several processes such as transmission of nerve impulses and maintaining the ion balance. A simple model for such a concentration cell involving a metal M is:
$M (s) | M^{+} (a q; 0.05 m o l a r) | | M^{+} (a q; 1 m o l a r) | M (s)$
For the above electrolytic cell the magnitude of the cell potential $| E_{c e l l} | = 70 m V$ .