If the 10th term of an A.P. is 35 and the 5th term is 20, then
A
a=9
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B
d=3
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C
a=8
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D
T9=32
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Solution
The correct options are Bd=3 Ca=8 DT9=32 Given, T10=a+9d=35⋯(i) T5=a+4d=20⋯(ii) From equation (i) and (ii), we get ⇒d=3⇒a=20−12=8 Now, T9=T10−d=35−3=32