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Question

If the 2nd term of an AP is 13 and the 5th term is 25, what is its 7th term?

A
30
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B
33
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C
37
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D
38
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Solution

The correct option is B 33
Let the first term of the AP be a, the common difference be d.
Then,
2nd term is a+d=13.......(1)
5th term is a+4d=25........(2)
Solving for d,

By Eq(2)Eq(1)
(a+4d)(a+d)=2513
3d=12
d=4
Hence, From (1)
a=13d=134=9
Now, 7th term is a+6d
Substituting values of a and d
7thterm=9+6×4=33

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