If the 2nd, 5th and 9th terms of a non-constant AP are in GP, then the common ratio of this GP is
A
43
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B
1
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C
85
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D
74
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Solution
The correct option is A43 Let a be the first term and d be the common difference. Then, we have a+d,a+4d,a+8d in GP
i.e., (a+4d)2=(a+d)(a+8d) ⇒a2+16d2+8ad=a2+8ad+ad+8d2 ⇒8d2=ad ⇒8d=a[∵d≠0]
Now, common ratio, r=a+4da+d=8d+4d8d+d=12d9d=43