( a) 5th
T3 = a + 2d = 4 ...(i)
T9 = a + 8d = -8 ...(ii)
On subtracting (i) from (ii), we get:
⇒ 6d = -12
⇒ d = -2
Putting the value of d in (i), we get:
⇒ a - 4 = 4
⇒ a = 8
Let the Tn term be 0.
Then Tn = 0
⇒ a + (n - 1)d = 0
⇒ 8 + (n - 1) ⨯ (-2) = 0
⇒ 2n = 10
⇒ n = 5
Hence, the 5th term of the AP is 0.