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Question

If the 4-digit number x27y is exactly divisible by 9, then the least value of (x + y) is

(a) 0

(b) 3

(c) 6

(d) 9

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Solution

x27y is exactly divisible by 9

The sum of its digits must be divisible by 9

x + 2 + 7 + y = x + y + 9 is divisible by 9

Least value of x + y = 0 as 0 + 9 = 9 is exactly divisible by 9 (a)


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