If the 4-digit number x27y is exactly divisible by 9, then the least value of (x + y) is
(a) 0
(b) 3
(c) 6
(d) 9
∵ x27y is exactly divisible by 9
∴ The sum of its digits must be divisible by 9
∴ x + 2 + 7 + y = x + y + 9 is divisible by 9
∴ Least value of x + y = 0 as 0 + 9 = 9 is exactly divisible by 9 (a)