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Question

If the 7th and 13th terms of an AP are 34 and 64 respectively, then its 18th term would be ____


A
87
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B
88
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C
89
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D
90
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Solution

The correct option is C 89

The 7th term of the A.P is
a+6d=34(1)

The 13th term of the A.P is
a+12d=64(2)Solving (2)(1),a+12da6d=64346d=30 d=5Substituting d in (1)a+6(5)=34a=4a18=4+(17)5=89


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