If the 7th and 13th terms of an AP are 34 and 64 respectively, then its 18th term would be ____
The 7th term of the A.P is
a+6d=34−−−(1)
The 13th term of the A.P is
a+12d=64−−−(2)Solving (2)−(1),a+12d−a−6d=64−346d=30⟹ d=5Substituting d in (1)a+6(5)=34⟹a=4∴a18=4+(17)5=89