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Question

If the A.M is twice the G.M. of the numbers a and b, then a:b will be

A
232+3
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B
2+323
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C
323+2
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D
3+232
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Solution

The correct options are
A 232+3
B 2+323
If a and b are in gp then let a =ar and b=a/r

AM=2GM

a+b/2=2ab

a+b=4ab

Put a and b in this

ar+a/r=4(ar)(a/r)

a(r+1/r)=4a2

r+1r=4

r24r+1=0

r=2+3,23
a=2+3,b=23
Now we have

a:b=2+323

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