If the above radial probability curve indicates ' $2 s$ ' orbital, the distance between the peak points $X$ , $Y$ is:

2.07 ˚ A

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1.59 ˚ A

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0.53 ˚ A

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2.12 ˚ A

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Solution

The correct option is D $2.12 ˚ A$
According to graph two maxima occurs at X and Y Here X = 2 $a_{0}$ and y= $6 a_{0}$ .
So, distance between these two will be $4 a_{0} = 2.12 A^{0}$

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Similar questions

List - I	List - II
I) Radial probability distribution curve of 3s orbital	a) $1.1 ˚ A$
II) Distance of maximum probability of 1s electron	b) 1s orbital
III) Radial node for a 2s electron	c) 3 peaks, 2 radial nodes
IV) No spherical nodes	d) $0.53 ˚ A$

s

(Ψ)

3

2

(Ψ)

H

4

3

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