Question

If the absolute temperature of a gas having volume $Vc{m}^3$ is doubled and the pressure is reduced to half, the final volume will be

• A.
  $0.25V$
• B.
  $0.50V$
• C.
  $2V^2$
• D.
  $4V$

Answer 1

The correct option is D

$4V$
Ideal Gas equation

$PV=nRT{V}_1=Vc{m}^3;V_2=?T_1=T;T_2=2T{P}_1=P;P_2=\frac{P}{2}\frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}\frac{P\times V}{T}=\frac{P\times V_2}{2\times 2T}{V}_2=4V$