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Satellite Launch Vehicle and Jounney to PSLV

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If the acceleration due to gravity. g. is 10msa is 10m/s at the n at a height of surface of the earth (radius 6400 km), the 1600 km the value of g will be (in m/ s2)

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Similar questions

Q. If the acceleration due to gravity, g, is 10

m / s^{2}

at the surface of the earth (radius 6400 km), then at a height of 1600 km the value of g will be ( in

m / s^{2}

)

Q. Calculate the acceleration due to gravity at a point

64 k m

32 k m

below the surface of earth.
Given Radius of Earth

= 6400 k m

. Acceleration due to gravity at the surface of earth

= 9.8 m s^{- 2}

Q. The value of acceleration due to gravity at a depth of

1600 k m

is equal to [Radius of earth

= 6400 k m

]

Q. (a) Assuming the earth to be a sphere of uniform density, calculate the value of acceleration due to gravity at a point (i)

1600

km above the earth, (ii)

1600

km below the earth, (b) Also find the rate of variation of acceleration due to gravity above and below the earth's surface. Radius of earth

= 6400

g = 9.8 m / s^{2}

Q. The height at which the value of acceleration due to gravity becomes

50 %

of that at the surface of the earth

.

(radius of the earth =

6400 k m

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