If the additive inverse of 3-7 is multiplied with the multiplicative inverse of 3-7- then the result is-

Additive inverse of nbsp;3/7 is 3/7. Multiplicative inverse of nbsp;3/7 is 7/3. Now, multiplying them, we get 3/7× nbsp; 7/3 = 1 So, option (c) is ...

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Standard VII

Mathematics

Addition and Subtraction of Rational Numbers

If the additi...

Question

If the additive inverse of $\frac{3}{7}$ is multiplied with the multiplicative inverse of $\frac{3}{7}$ , then the result is:

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Solution

Additive inverse of $\frac{3}{7}$ is - $\frac{3}{7}$ .

Multiplicative inverse of $\frac{3}{7}$ is $\frac{7}{3}$ .

Now, multiplying them, we get

- $\frac{3}{7}$ $\times \frac{7}{3}$ = -1

So, option (c) is correct.

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If the additive inverse of 37 is multiplied with the multiplicative inverse of 37, then the result is:

Additive inverse of 37 is -37. Multiplicative inverse of 37 is 73. Now, multiplying them, we get -37×73 = -1 So, option (c) is correct.

If the additive inverse of $\frac{3}{7}$ is multiplied with the multiplicative inverse of $\frac{3}{7}$ , then the result is:

Additive inverse of $\frac{3}{7}$ is - $\frac{3}{7}$ .

Multiplicative inverse of $\frac{3}{7}$ is $\frac{7}{3}$ .

Now, multiplying them, we get

- $\frac{3}{7}$ $\times \frac{7}{3}$ = -1

So, option (c) is correct.