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Standard XII

Physics

Pressure

If the air de...

Question

If the air density were uniform, then the height of the atmosphere above the sea level to produce a normal atmospheric pressure of 1.0 x 10 $^{5}$ Pa is(density of air is 1.3 kg/m $^{3}$ , g $=$ 10m/s $^{2}$ ):

0.77 km

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7.7 km

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77 km

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0.077 km

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Solution

The correct option is B 7.7 km
$ρ g h = 1 \times 10^{5}$
$\Rightarrow h = \frac{10^{5}}{ρ g} = \frac{10^{5}}{1.3 \times 10} = 7.7 k m$

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Similar questions

Q. At sea level, the atmospheric pressure is

1.04 \times 10^{5} P a

. Assuming

g = 10 m s^{- 2}

and density of air to be uniform and equal to

1.3 k g m^{- 3}

, find the height of the atmosphere.

Q. Assuming that the atmosphere has the same density anywhere as at sea level

(ρ = 1.3 {kg/m}^{3})

and

g

to be constant

(g = 10 {m/s}^{2})

, what should be the approximate height of the atmosphere so that the atmospheric pressure at sea level is

p_{0} = 1.01 \times 10^{5} {N/m}^{2}

Q. Assuming that the atmosphere has the same density anywhere as at sea level

(ρ = 1.3 {kg/m}^{3})

and

g

to be constant

(g = 10 {m/s}^{2})

, what should be the approximate height of the atmosphere so that the atmospheric pressure at sea level is

p_{0} = 1.01 \times 10^{5} {N/m}^{2}

To what extent the atmosphere is extended above the surface of the Earth, assuming the density of air to be uniform [1.3 kg/m³] and pressure at the surface of Earth to be 10⁵ Pa. (Also assume the Earth to be perfectly spherical and no variation in 'g' due to height.)

Q. Calculate the approximate height (h) of Earth's atmosphere extending above the surface of the Earth, assuming the density of air to be uniform [

1.3 k g m^{- 3}

] and pressure at the surface of Earth to be

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. (Assume the Earth to be perfectly spherical and no variation in 'g' due to height).

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If the air density were uniform, then the height of the atmosphere above the sea level to produce a normal atmospheric pressure of 1.0 x 105 Pa is(density of air is 1.3 kg/m3 , g = 10m/s2):

The correct option is B 7.7 kmρgh=1×105⇒h=105ρg=1051.3×10=7.7km

If the air density were uniform, then the height of the atmosphere above the sea level to produce a normal atmospheric pressure of 1.0 x 10 $^{5}$ Pa is(density of air is 1.3 kg/m $^{3}$ , g $=$ 10m/s $^{2}$ ):

The correct option is B 7.7 km
$ρ g h = 1 \times 10^{5}$
$\Rightarrow h = \frac{10^{5}}{ρ g} = \frac{10^{5}}{1.3 \times 10} = 7.7 k m$