If the air density were uniform, then the height of the atmosphere above the sea level to produce a normal atmospheric pressure of 1.0 x 105 Pa is(density of air is 1.3 kg/m3 , g = 10m/s2):
A
0.77 km
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
7.7 km
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
77 km
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.077 km
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B 7.7 km ρgh=1×105 ⇒h=105ρg=1051.3×10=7.7km