If the altitude of the sun is 60- the height of a tower which casts a shadow of length 30 m is -

The correct option is B 30√(3)m tan 60 #176; = h x ⇒√( 3 ) = h 30 ⇒ h=30√( 3 ) m Hence, the answer is 30√( 3 ) m. ...

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Standard X

Mathematics

Calculating Heights and Distances

If the altitu...

Question

If the altitude of the sun is $60^{\circ}$ , the height of a tower which casts a shadow of length 30 m is :

30 \sqrt{3} m

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15m

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\frac{30}{\sqrt{3}} m

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15 \sqrt{2} m

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Solution

The correct option is B $30 \sqrt{3} m$

$tan 60 ° = \frac{h}{x}$
$\Rightarrow \sqrt{3} = \frac{h}{30}$
$\Rightarrow h = 30 \sqrt{3} m$
Hence, the answer is $30 \sqrt{3} m .$

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Similar questions

If altitude of the sun is 60^o, the height of a tower which casts a shadow of length 30 m is:

Q. If the altitude of the sun is at

60^{\circ}

, then the height of the vertical tower that will cast a shadow of length 30 mis

Q. If the altitude of the sum is at 60°, then the height of the vertical tower that will cast a shadow of length 30 m is

(a)

10 \sqrt{3}

m

(b) 15 m

(c)

\frac{30}{\sqrt{3}} m

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Q. If the altitude of the sun is at

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then the height of the vertical tower that will cast a shadow of length 20 m is

The shadow of a tower standing on a level ground is found to be 60 m longer when the Sun’s altitude is $30^{\circ}$ than when it is $60^{\circ}$ . Find the height of the tower.

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If the altitude of the sun is 60∘, the height of a tower which casts a shadow of length 30 m is :

The correct option is B 30√3mtan60°=hx⇒√3=h30⇒h=30√3mHence, the answer is 30√3m.

If the altitude of the sun is $60^{\circ}$ , the height of a tower which casts a shadow of length 30 m is :

The correct option is B $30 \sqrt{3} m$

$tan 60 ° = \frac{h}{x}$
$\Rightarrow \sqrt{3} = \frac{h}{30}$
$\Rightarrow h = 30 \sqrt{3} m$
Hence, the answer is $30 \sqrt{3} m .$