If the amount of heat given to a system be 105 joules and the amount of work done by the system be 55 joules, then the change in the internal energy of the system (in Joule) is
A
50
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B
120
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C
55
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D
160
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Solution
The correct option is A50 From first law of thermodynamic, △U=q+w where q = Heat entering the system w = Work done on the system △U = Change in Internal energy Given, q = 105 J, w = -55 J ⇒△U=105−55=50J