Given, the angle (2a−10)∘ is 30 degree more than a right angle. ∴(2a−10)∘=30∘+90∘
⇒(2a−10)∘=120∘
⇒2a=110∘ ⇒a=55∘
If A, B and C are the interior angles of a right-angle triangle, right-angled at B then find the value of A, given that tan2A=cot(A–30∘) and 2A is an acute angle.