Question

if the angle between the radii of a circle is ${130}^0$ then the angle between the tangents at the ends of the radii is

• A. ${90}^0$
• B. ${70}^0$
• C. ${50}^0$
• D. ${40}^0$

Answer 1

The correct option is C ${50}^0$

$x+{130}^0+{90}^0+{90}^0=360$

$\Rightarrow x=360-(130+180)$

$\Rightarrow x={50}^0$

Hence, the answer is ${50}^0.$