If the angle between the vector A- and B-is - the value of the product B- x A- A- is equal to -

The correct option is A Zero (B⃗×A⃗).A⃗=(BASinΘ )(n⃗.A⃗)=0 Since n̂ #160;is perpendicular to both A⃗ amp; B⃗ ...

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Byju's Answer

Standard XII

Physics

Multiplication with Vectors

If the angle ...

Question

If the angle between the vector $\to A$ and $\to B$
is $θ$ , the value of the product $(\to B$ x $\to A) . \to A$ is equal to -

Zero

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^{2}

Sin

θ

cos

θ

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^{2}

cos

θ

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^{2}

Sin

θ

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Solution

The correct option is A Zero
$(\to B \times \to A) . \to A = (B A S i n Θ) (\to n . \to A) = 0$
Since $^n$ is perpendicular to both $\to A$ & $\to B$

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Similar questions

Q. If the angle between the vectors

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θ

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are two vectors and

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| \to A \times \to B | = \sqrt{3} (\to A \cdot \to B)

the value of

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be three non-zero vectors such that no two of them are collinear and

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If the angle between the vector →A and →Bis θ, the value of the product (→B x →A).→A is equal to -

The correct option is A Zero(→B×→A).→A=(BASinΘ)(→n.→A)=0Since ^n is perpendicular to both →A & →B

If the angle between the vector $\to A$ and $\to B$
is $θ$ , the value of the product $(\to B$ x $\to A) . \to A$ is equal to -

The correct option is A Zero
$(\to B \times \to A) . \to A = (B A S i n Θ) (\to n . \to A) = 0$
Since $^n$ is perpendicular to both $\to A$ & $\to B$