If the angle between the vectors A- and B- is - then the value of the product B-A- A- equals

The correct option is B zero (B⃗×A⃗)·A⃗= BAsinθn̂·A⃗=0 #160;Vector A⃗ and n̂ are perpendicular to each other as direction of n̂ ...

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Byju's Answer

Standard XII

Physics

Multiplication with Vectors

If the angle ...

Question

If the angle between the vectors $\to A$ and $\to B$ is $θ$ , then the value of the product $(\to B \times \to A)$ . $\to A$ equals

B A^{2} sin θ

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B A^{2} cos θ sin θ

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B A^{2} cos θ

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z e r o

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Solution

The correct option is B $z e r o$
$(\to B \times \to A) \cdot \to A = - B A sin θ^n \cdot \to A = 0$
Vector $\to A$ and $^n$ are perpendicular to each other as direction of $^n$ can be given by right hand screw rule.
Dot product of two vectors is zero when they are perpendicular to each other.

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If the angle between the vectors →A and →B is θ, then the value of the product (→B×→A). →A equals

The correct option is B zero(→B×→A)⋅→A=−BAsinθ^n⋅→A=0 Vector →A and ^n are perpendicular to each other as direction of ^n can be given by right hand screw rule.Dot product of two vectors is zero when they are perpendicular to each other.

If the angle between the vectors $\to A$ and $\to B$ is $θ$ , then the value of the product $(\to B \times \to A)$ . $\to A$ equals

The correct option is B $z e r o$
$(\to B \times \to A) \cdot \to A = - B A sin θ^n \cdot \to A = 0$
Vector $\to A$ and $^n$ are perpendicular to each other as direction of $^n$ can be given by right hand screw rule.
Dot product of two vectors is zero when they are perpendicular to each other.