Question

If the angle between the velocity $\overline{A}$ and $\overline{B}$ is ${}^{\prime }\theta {}^{\prime }$ the value of the product $(\overline{B}\times \overline{A}).\overline{A}$ is equal to

• A. $B{A}^2\cos \theta$
• B. $B{A}^2\sin \theta$
• C. $B{A}^2\sin \theta \cos \theta$
• D. Zero

Answer 1

The correct option is D Zero

Given, Two velocities $\overrightarrow{A},\overrightarrow{B},Angle=\theta$

Let $B\times A=R$

$B\times A$ is a vector which is perpendicular to oh B and A

$(B\times A).A=R.A$

R is the perpendicular toA sot product wii be zero,

SO $(B\times A).A=0$