If the angle between two vectors is 60o, then →A⋅→B|→A×→B| is :
Q=60∘−
¯A.¯B∣∣¯AׯB∣∣=∣∣¯A∣∣∣∣¯B∣∣cosθ∣∣¯A∣∣∣∣¯B∣∣sinθ
cot60∘
1√3.