Question

If the angle of deviation produced by a thin prism of referactive index $\mu =1.6$ is $3^{\circ }$. Then the angle of the thin prism is :

• A. $5^{\circ }$
• B. $4^{\circ }$
• C. $6^{\circ }$
• D. $2^{\circ }$

Answer 1

The correct option is A $5^{\circ }$

We know that, in case of thin prism,
$\delta =(\mu -1)A$
$A=\frac{\delta }{(\mu -1)}$

Here, $\delta =3^{\circ },$
$\mu =1.6$
So, $A=\frac{3}{(1.6-1)}$
$\Rightarrow A=\frac{3}{0.6}$
$A=5^{\circ }$

Hence, Option $\left(a\right)$ is correct.