If the angle of dip at a certain place is $45^{o}$ then the horizontal component $H$ , vertical component $V$ and total intensity $I$ of earth's magnetic field have the correct relationship given by :

H = \sqrt{2} V

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I = \sqrt{2} V

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H = 2 V

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H = \sqrt{2} H

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Solution

The correct option is B $I = \sqrt{2} V$
Horizontal and Vertical component of Magnetic field intensity is given by,
$I cos 45^{o} = H$
$I sin 45^{o} = V$
$H = V$
$I = \sqrt{2} H$
$I = \sqrt{2} V$

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If the angle of dip at a certain place is 45o then the horizontal component H, vertical component V and total intensity I of earth's magnetic field have the correct relationship given by :

The correct option is B I=√2VHorizontal and Vertical component of Magnetic field intensity is given by,Icos45o=HIsin45o=VH=VI=√2HI=√2V

If the angle of dip at a certain place is $45^{o}$ then the horizontal component $H$ , vertical component $V$ and total intensity $I$ of earth's magnetic field have the correct relationship given by :

The correct option is B $I = \sqrt{2} V$
Horizontal and Vertical component of Magnetic field intensity is given by,
$I cos 45^{o} = H$
$I sin 45^{o} = V$
$H = V$
$I = \sqrt{2} H$
$I = \sqrt{2} V$