Question

If the angle of elevation of a tower from a distance of 100 m from its foot is ${60}^{\circ }$, then the height of the tower is

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

Let h be the height of the tower.
Then, $tan{60}^{\circ }=\frac{h}{100}$
$\sqrt{3}=\frac{h}{100}$
$h=100\sqrt{3}m$