Question

If the angle of elevation of a tower from a distance of 100 metres from its foot is 60°, then the height of the tower is

(a) 100$\sqrt{3}$ m

(b) $\frac{100}{\sqrt{3}}m$

(c) $50\sqrt{3}$

(d) $\frac{200}{\sqrt{3}}m$

Answer 1

Let be the height of tower is meters

Given that: angle of elevation is from tower of foot and distance meters.

Here, we have to find the height of tower.

So we use trigonometric ratios.

In a triangle,

Hence correct option is _.