Question

If the angle of polarization for a medium is $60°$, what will be critical angle?

• A. ${\sin }^{-1}\sqrt{3}$
• B. ${\cos }^{-1}\sqrt{3}$
• C. ${\tan }^{-1}\sqrt{3}$
• D. ${\sin }^{-1}\frac{1}{\sqrt{3}}$

Answer 1

The correct option is D ${\sin }^{-1}\frac{1}{\sqrt{3}}$

By Brewster's law
$\mu =\tan {\theta }_B$
$\Rightarrow \mu =\tan 60°\Rightarrow \mu =\sqrt{3}$
Also critical angle
$C={\sin }^{-1}\left(\frac{1}{\mu }\right)\Rightarrow C={\sin }^{-1}\left(\frac{1}{\sqrt{3}}\right)$