Question

If the angle $\theta ={60}^{\circ }$ and $cos\theta =\frac{1}{2}$, find the value of sec $\theta$.

Answer 1

$\theta ={60}^{\circ }$
Hence, $\sin \theta =\sin {60}^{\circ }=\frac{\sqrt{3}}{2}$
$\cos \theta =\cos {60}^{\circ }=\frac{1}{2}$
$\tan \theta =\tan {60}^{\circ }=\sqrt{3}$
$\sec \theta =\sec {60}^{\circ }=2$