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Potential at a General Point Due to a Dipole

If the angles...

Question

If the angles made by a straight line with the coordinate axes are $α, \frac{π}{2} - α, β$ then $β =$

0

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\frac{π}{6}

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\frac{π}{2}

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π

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Solution

The correct option is A $\frac{π}{2}$
Given angles are $α, 90^{0} - α, β$

The summations of cosines of these angles has to be $1$ .

So, ${cos}^{2} α + {cos}^{2} (90^{0} - α) + {cos}^{2} β = 1$
${cos}^{2} α + {sin}^{2} α + {cos}^{2} β = 1$

${cos}^{2} β = 0$

$β = \frac{π}{2}$

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