If the angles of a quadrilateral are in the ratio 3:4:6:7, then the quadrilateral is a
Angles C & D
Let ABCD be the given quadrilateral let the angles of the quadrilateral be 3x,4x,6x and 7x.
3x+4x+6x+7x=360∘ (sum of angles of a quadrilateral)
20x = 360
x=18∘
Therefore the angles are 3(18)=54,4(18)=72∘,6(18)=108∘ and 7(18)=126∘
Sum of adjancent angles 72∘+108∘=180∘
∴AB||CD (Cointeriar angles are supplementary).
∴ABCD is a trapezium. Hence (D)