If the angles of a triangle are 2 x- 3 x- and 4 x- then find the value of the largest angle-A- 40-B- 30-C- 60-D- 80-

The correct option is D 80^∘We know that sum of the three angles of a triangle = 180^∘ Therefore, 2x + 3x + 4x = 180^∘ or, 9x = 180^∘, x =180/9 = 20^∘ Larges ...

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Byju's Answer

Standard VI

Mathematics

Side Property of Triangle

If the angles...

Question

If the angles of a triangle are $2 x^{\circ}$ , $3 x^{\circ}$ and $4 x^{\circ}$ , then find the value of the largest angle.

40^{\circ}

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60^{\circ}

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30^{\circ}

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80^{\circ}

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Solution

The correct option is D $80^{\circ}$
We know that sum of the three angles of a triangle = $180^{\circ}$

Therefore, $2 x + 3 x + 4 x = 180^{\circ}$

$o r, 9 x = 180^{\circ}$ ,
$x = \frac{180}{9} = 20^{\circ}$
$Largest angle = 4 x = 4 \times 20 = 80^{o}$

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If the angles of a triangle are 2x∘, 3x∘​ and 4x∘, then find the value of the largest angle.

The correct option is D 80∘We know that sum of the three angles of a triangle = 180∘​ Therefore, 2x+3x+4x=180∘​ or,9x=180∘, x=1809=20∘ Largest angle = 4x=4×20=80o

If the angles of a triangle are $2 x^{\circ}$ , $3 x^{\circ}$ and $4 x^{\circ}$ , then find the value of the largest angle.

The correct option is D $80^{\circ}$
We know that sum of the three angles of a triangle = $180^{\circ}$

Therefore, $2 x + 3 x + 4 x = 180^{\circ}$

$o r, 9 x = 180^{\circ}$ ,
$x = \frac{180}{9} = 20^{\circ}$
$Largest angle = 4 x = 4 \times 20 = 80^{o}$