Relation between Inradius and Perimeter of Triangle
If the angles...
Question
If the angles of a triangle are 300 and 450 and the included side is (√3+1) cm, the area of the triangle is 12(√3+1) sq.cm.
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Solution
Let ∠A=300,∠B=450 so that AB=c=(√3+1)..............(1) Also ∠C=1800−(300+450)=1050 ∴sinC=sin(900+150)=cos150 or sinC=cos(450−300)=11√(2)(√3+1)=12√(2).c by (1) ...........(2) ∴b=sinB.2√2=2∵B=450 ∴△=12bcsinA=12.(√3+1).12=12(√3+1).