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Question

If the angles of elevation of the top of a tower from three collinear points A, B and C, on a line leading to the foot of the tower, are 30, 45, and 60 respectively, then the ratio AB:BC is

A
1:3
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B
2:3
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C
3:1
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D
3:2
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Solution

The correct option is C 3:1


PB bisects APC, therefore AB : BC = PA : PC
Also ΔAPQ,sin 30=hPAPA=2h
And in ΔCPQ,sin60=hPCPA=2h3
AB:BC=2h:2h3=3:1

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