If the anions (A) form hexagonal closest packaging and cations (C) occupy only two-third octahedral voids in it, then the general formula of the compound is :

C A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C A_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{2} A_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C_{3} A_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $C_{2} A_{3}$
In hexagonal closest packaging, the number of octahedral voids is equal to the number of atoms.
Therefore the general formula of the compound is $C_{2 / 3} A$ or $C_{2} A_{3}$

Suggest Corrections

Similar questions

\frac{2}{3}

The anions (A) form hexagonal closest packing and cation (C) occupy only 2/3 of octahedral voids in it, then the general formula of the compound is

(A)

(M)

Join BYJU'S Learning Program