Question

If the anti-neutrino had a mass of $3eV/c^2$ (where c is the speed of light) instead of zero mass, what should be the range of the kinetic energy, K, of the electron?

• A. $0\le K\le 0.8\times {10}^{6}eV$
• B. $0\le K<0.8\times {10}^{6}eV$
• C. $3.0eV\le K<0.8\times {10}^{6}eV$
• D. $3.0eV\le K\le 0.8\times {10}^{6}eV$

Answer 1

The correct option is B $0\le K<0.8\times {10}^{6}eV$

Minimum kinetic energy of electron can be zero or greater than zero. But maximum kinetic energy will be less than $0.8\times 106eV$.