Question

If the area of a rectangle is $200$ sq.m and the difference of its length and breadth is $10$ cm, find its length, breadth and perimeter.

Answer 1

Let length and breadth be $l$ and $l-10$

area=$l(l-10)$=$200$

$l^2$$-10l$$-200=$$0$

$(l-20)(l+10)$=$0$

$\therefore l=20$

length=$20m$

breadth=$10m$

perimeter$=2(20+10)$

$=60m$