If the area of a rectangle is 24 m² and its perimeter is 20 m, the equation to find its length and breadth would be:

x²- 10x - 24 = 0

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x²+ 10x + 28 = 0

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x²- 10x + 24 = 0

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x²+ 1 2x + 24 = 0

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Solution

The correct option is C
x²- 10x + 24 = 0

2(l + b) = 20

l + b = 10

Area of rectangle = 24

lb = 24

If l and b are the roots of the quadratic equation, then the required quadratic equation is

x²- 10x + 24 = 0

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If the area of a rectangle is 24 m2 and its perimeter is 20 m, the equation to find its length and breadth would be:

The correct option is C x2 - 10x + 24 = 02(l + b) = 20 l + b = 10 Area of rectangle = 24 lb = 24 If l and b are the roots of the quadratic equation, then the required quadratic equation is x2 - 10x + 24 = 0

If the area of a rectangle is 24 m² and its perimeter is 20 m, the equation to find its length and breadth would be:

The correct option is C
x²- 10x + 24 = 0

2(l + b) = 20

l + b = 10

Area of rectangle = 24

lb = 24

If l and b are the roots of the quadratic equation, then the required quadratic equation is

x²- 10x + 24 = 0