If the area of a rhombus is 24 $c m^{2}$ and one of its diagonals is 8 cm long, then find the length of the other diagonal.

2 cm

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4 cm

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6 cm

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8 cm

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Solution

The correct option is C 6 cm
$G i v e n : A r e a = 24 c m^{2}$
$D i a g o n a l d_{1} = 8 c m$
$A r e a o f t h e r h o m b u s = \frac{1}{2} \times d_{1} \times d_{2}$
$24 = \frac{1}{2} \times d_{1} \times d_{2}$
$24 = \frac{1}{2} \times 8 \times d_{2}$
$24 = 4 \times d_{2}$
$d_{2} = 6 c m$
Hence, the length of other diagonal is 6 cm.

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If the area of a rhombus is 24 cm2 and one of its diagonals is 8 cm long, then find the length of the other diagonal.

The correct option is C 6 cmGiven:Area=24cm2 Diagonal d1=8 cm Area of the rhombus=12×d1×d2 24=12×d1×d2 24=12×8×d2 24=4×d2 d2=6cm Hence, the length of other diagonal is 6 cm.

If the area of a rhombus is 24 $c m^{2}$ and one of its diagonals is 8 cm long, then find the length of the other diagonal.