If the area of a square is 32 cm $^{2}$ then find the diagonal of the square

8 cm

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4 \sqrt{2}

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8 \sqrt{2}

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4 cm

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Solution

The correct option is A 8 cm
Area of the square $= {s i d e}^{2} = 32$
$=> s i d e = \sqrt{32} = 4 \sqrt{2}$
Diagonal of the square $= \sqrt{2} \times s i d e = \sqrt{2} \times 4 \sqrt{2} = 2 \times 4 = 8$

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