If the area of a square is 4 times the area of rectangle with length 8m and breadth 2m, what is the side of the square?

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Solution

The correct option is D 8m
Area of the rectangle = length x breadth = 8m x 2m = 16 $m^{2}$
Area of square = 4 x area of rectangle = 4 x 16 = 64 $m^{2}$
Also we know, area of square = $a^{2}$ , where a is the side of square.
So, 64 = $a^{2}$
$\Rightarrow$ a = 8m
So, the side of the required square = 8m

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If the area of a square is 4 times the area of rectangle with length 8m and breadth 2m, what is the side of the square?

The correct option is D 8mArea of the rectangle = length x breadth = 8m x 2m = 16 m2 Area of square = 4 x area of rectangle = 4 x 16 = 64 m2 Also we know, area of square = a2, where a is the side of square. So, 64 = a2 ⇒ a = 8m So, the side of the required square = 8m