Question

If the area of a trapezium with parallel sides of length 30 cm and 20 cm, respectively, is 265 sq cm, what is its height?

Answer 1

Lengths of the parallel sides of the trapezium are 30 cm and 23 cm.
Area of the trapezium is 265 sq cm.
Area of a trapezium = $\frac{1}{2}$ (Sum of lengths of parallel sides)×(Height)
265 sq cm= $\frac{1}{2}$ × ( 30 cm +23 cm) × (Height)

or Height = $\frac{265\times 2}{53}cm$
∴ Height = 10 cm