Question

If the area of a triangle is $1176m^2$ and base : corresponding altitude is $3:4$, then the altitude of the triangle is:

• A. $42m$
• B. $52m$
• C. $54m$
• D. $56m$

Answer 1

The correct option is D $56m$

Let base$=3x$ and altitude$=4x$
$\therefore$ area of $\Delta =\frac{1}{2}\times base\times altitude$
$\frac{1}{2}\times 3x\times 4x=1766x^2=1176x^2=196x=\sqrt{196}=14m$
$\therefore$altitude$=4\times 14=56m$