If the area of base of a cone is 49- m2 and its CSA is 175- m2- then its height is m-

The correct option is A 24Area of base = nbsp;πr^2 49π = nbsp;πr^2 ⇒ r = 7 m. CSA = nbsp;πrl 175π = nbsp;π (7) l ⇒ l = 25 m. We know, r^2 + h^2 = l^2 ...

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If the area of base of a cone is 49 $π m^{2}$ and its CSA is 175 $π m^{2}$ , then its height is __ m.
24

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Solution

The correct option is A 24
Area of base = $π r^{2}$
49 $π$ = $π r^{2}$
$\Rightarrow r = 7 m .$

CSA = $π r l$
175 $π$ = $π (7) l$
$\Rightarrow l = 25 m .$

We know, $r^{2} + h^{2} = l^{2}$
$h^{2} = 25^{2} - 7^{2}$
$h^{2} = 24^{2}$
[7, 24, 25 is a pythagorean triplet]
$\Rightarrow h = 24 m$

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If the area of base of a cone is 49π m2 and its CSA is 175π m2, then its height is __ m.24

The correct option is A 24Area of base = πr2 49π = πr2 ⇒r=7m. CSA = πrl 175π = π (7) l ⇒l=25m. We know, r2+h2=l2 h2=252−72 h2=242 [7, 24, 25 is a pythagorean triplet] ⇒h=24m

If the area of base of a cone is 49 $π m^{2}$ and its CSA is 175 $π m^{2}$ , then its height is __ m.
24

The correct option is A 24
Area of base = $π r^{2}$
49 $π$ = $π r^{2}$
$\Rightarrow r = 7 m .$

CSA = $π r l$
175 $π$ = $π (7) l$
$\Rightarrow l = 25 m .$

We know, $r^{2} + h^{2} = l^{2}$
$h^{2} = 25^{2} - 7^{2}$
$h^{2} = 24^{2}$
[7, 24, 25 is a pythagorean triplet]
$\Rightarrow h = 24 m$