If the area of base of a cone is 49- m2 and its CSA is 175- m2- then its height is -

The correct options are B 25 m C 24 mArea of base = nbsp;πr^2 49π = nbsp;πr^2 r = 7 m. CSA = nbsp;πrl 175π = nbsp;π (7) l l = 25 m. We know, r^2 + h^2 ...

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Standard X

Mathematics

Cone

If the area o...

Question

If the area of base of a cone is 49 $π m^{2}$ and its CSA is 175 $π m^{2}$ , then its height is .

34 m

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25 m

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24 m

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Solution

The correct options are
B 25 m
C 24 m
Area of base = $π r^{2}$
49 $π$ = $π r^{2}$
r = 7 m.

CSA = $π r l$
175 $π$ = $π (7) l$
l = 25 m.

We know, $r^{2} + h^{2} = l^{2}$
$h^{2} = 25^{2} - 7^{2}$
$h^{2} = 24^{2}$
[7, 24, 25 is a pythagorean triplet]
h=24 m

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If the area of base of a cone is 49π m2 and its CSA is 175π m2, then its height is .

The correct options are B 25 m C 24 mArea of base = πr2 49π = πr2 r = 7 m. CSA = πrl 175π = π (7) l l = 25 m. We know, r2+h2=l2 h2=252−72 h2=242 [7, 24, 25 is a pythagorean triplet] h=24 m

If the area of base of a cone is 49 $π m^{2}$ and its CSA is 175 $π m^{2}$ , then its height is .

The correct options are
B 25 m
C 24 m
Area of base = $π r^{2}$
49 $π$ = $π r^{2}$
r = 7 m.

CSA = $π r l$
175 $π$ = $π (7) l$
l = 25 m.

We know, $r^{2} + h^{2} = l^{2}$
$h^{2} = 25^{2} - 7^{2}$
$h^{2} = 24^{2}$
[7, 24, 25 is a pythagorean triplet]
h=24 m