Question

If the area of $\Delta ABC$ is 8 sq. units then the area of $\Delta$ formed by joining the mid point of the sides of $\Delta$ ABC is

• A. 4 sq. units
• B. 16 sq.units
• C. 10 sq.unit
• D. 2 sq.units

Answer 1

The correct option is D 2 sq.units

Theorem:- According to theorem

If we join the middle point of the sides of triangle then triangles formed is $\frac{1}{4}$ of the given triangle

So, here

area of $△PQR=\frac{1}{4}Areaof△ABC$

$=\frac{1}{4}\times \theta$

$=2sq.unit$