Question

# If the area of the base of a right circular cone is $$51\ m^2$$ and volume is $$68\ m^3$$, then its vertical height is:

A
3.5 m
B
4 m
C
4.5 m
D
5 m

Solution

## The correct option is B $$4\ m$$The area of the base of a right circular cone $$A=51\ m^2$$Volume $$V=68\ m^3$$Then, to find $$h$$,$$\dfrac{V}{A}=\dfrac{\dfrac{1}{3}\pi r^2 h}{\pi r^2}=\dfrac{68}{51}$$$$\implies h=\dfrac{3\times 68}{51}$$$$\implies h=4\ m$$Hence, option $$B$$ is correct.Mathematics

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