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Question

If the area of the base of a right circular cone is $$51\ m^2$$ and volume is $$68\ m^3$$, then its vertical height is:


A
3.5 m
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B
4 m
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C
4.5 m
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D
5 m
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Solution

The correct option is B $$4\ m$$
The area of the base of a right circular cone $$A=51\ m^2$$
Volume $$V=68\ m^3$$
Then, to find $$h$$,
$$\dfrac{V}{A}=\dfrac{\dfrac{1}{3}\pi r^2 h}{\pi r^2}=\dfrac{68}{51}$$
$$\implies h=\dfrac{3\times 68}{51}$$
$$\implies h=4\ m$$
Hence, option $$B$$ is correct.

Mathematics

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