If the area of the largest square is 64 cm2, the side length (in cm) of the smallest square will be:
A
2
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B
2√2
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C
4√2
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D
4
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Solution
The correct option is D 4 Given, area of the largest square, i.e. of S1 = 64 cm2
Side of square S1 = √area = √64 = 8 cm
Side of the square S1 = Diameter of the circle C1 = Diagonal of the square S2 = 8 cm
In the square S2, diagonal2 = side2 + side2 ⇒82 = 2side2 ⇒side2=32 ⇒side=√32=4√2 ∴SideofthesquareS2=4√2 cm
Side of the square S2 = Diameter of the circle C2 = Diagonal of the square S3 = 4√2 cm
In the square S3, diagonal2 = side2 + side2 ⇒(4√2)2 = 2side2 ⇒side2=16 ⇒side=√16=4 ∴SideofthesquareS3=4 cm