Question

If the area of the minor sector is 392. 5 sq. cm and the corresponding central angle is ${72}^{\circ }$, find the radius. $(\pi =3.14)$

Answer 1

Area of a sector of a circle of radius 'r' and angle
$\theta =\frac{\theta }{360}\pi R^2$
Hence, $392.5=\frac{72}{360}\times 3.14\times {Radius}^2$

$=>{Radius}^2=625$
$Radius=25$
Hence, Radius of the circle is $25cm$